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Solution: The above system of equations is set to formula ① and formula ② can be changed to: {15[(x-y)^2+2xy]-34xy}(x+3)^2-15=0[15 (x-y)^2-4xy](x+3)^2-15=0…③② can be changed to: 2x(x-y)+6(x-y)-2=0∴x(x-y)+3(x-y)- 1=0∴(x-y)(x+3
Notice of the Autonomous Region Education Department on Further Improving Online Teaching in Primary and Secondary Schools in Areas of Epidemics (with Course Schedule)